14 out of 2400 babies that were born at a maternity hospital died shortly after birth from colonic o

Use this as a sample to answer your question. If you need more help, post back!


p^2 + 2pq + q^2 = 1 and p + q = 1

p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population

p^2 = percentage of homozygous dominant individuals
q^2 = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals

We are given 6/2400 as the percentage of homozygous recessive individuals:

q^2 = 6/2400 = 0.0025

Using algebra, we can find q, the frequency of the recessive allele, which is lethal if homozygous.

q = sqrt(0.0025) = 0.05 = 5%

So 5 percent of the population is a heterozygous carrier of the lethal allele.

I don't understand where you got number 6 from?
Cause they give us numbers 14 and 2400....

and how would you go about this question?

2. 4 out of 2400 babies that were born at a maternity hospital died shortly after birth from colonic obstruction due to a recessive allele. What percent of the population would you expect to be carriers of the lethal allele?

It was assumed to be 6 out 2400. Sorry...

Thats alright!

Do you know how to solve the second question? 4 out of 2400 babies....

Thanks! I really appreciate it

Thanks!

thank you

thank you so much!