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jyang01 jyang01
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11 years ago
Using the Reciprocal and Pythagorean Identities, verify that both sides of this equation are equal.

tanx / (1-cosx) = cscx (1+secx)

I have tried this a million different ways and I cannot get both sides to equal each other.  Is it just me?  I start off with the Left Hand Side but every time I do something, the sines and cosines end up on the top of the division sign, and not the bottom (where they are supposed to be if they are going to equal the RHS.
I'm not sure if everyone knows what verifying an equation means, but you can only work with one side of the equation at a time.  You cannot bring parts from the right-hand side over to the left-hand side.
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11 years ago
Start with LHS and multiply numerator and denominator by (1+cosx) and you get tanx(1+cosx)/(1-cosx)(1+cosx).

The denominator, multiplied out, becomes 1 - cos^2x = sin^2 x:

= tanx(1+cosx)/(sin^2 x)

cancel out a sin in numerator and denominator because tanx = sinx/cosx and therefore tanx/sinx = 1/cosx = secx:

= secx(1+cosx) / sinx

distribute the secx:

= (secx + (secx)(cosx)) / sinx

secx = 1/cosx so (secx)(cosx) = 1:

= (secx + 1) / sinx

then take the sinx in the denominator and turn it into a cscx in the numerator because 1/sinx = cscx:

= cscx (1 + secx)

Hope this helps.
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