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11 years ago
Verifying a Trigonometric Identity

[tan(x+y) - tany] / [1+tan(x+y)tany] = tanx

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#1
11 years ago
Let a = (x+y)
[ tan(x+y) - tany ] / [ 1 + tan(x+y)tany ]
= [ tan(a) - tany ] / [ 1 + tan(a)tany ]
= tan(a-y) = tan(x+y-y) = tanx
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zzz1090zzz1090
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11 years ago
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This verified answer contains over 120 words.
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abciara101 Author
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#3
11 years ago
tan ( x + y ) - tan y
----------------------------
1 + tan ( x + y ) tany

tan [ ( x + y ) - y ]

tan x
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