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11 years ago
pH = pKa + log (unprotonated/protonated)

That's all I know but I can't figure out how to find the pH with the information that is given. Thank you.
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wrote...
11 years ago
Ka  = [H+][A-]/[HA]
50% ionized [A-] = [HA]
.: Ka = [H+]  or pKa = pH = 4.2

log(1) = 0
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