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iki08 iki08
wrote...
11 years ago
Given this equation do a mole to mole conversion:
Al(OH)3 +3HCl -------> AlCl3 + 3H20
Find the number of mole of acid neutralized if a tablet contains .200 mol of Al(OH)3.
I know you do moles of unknown over moles of known but which coeficents do u use? those from the product side or reactant sidde?
after that did u get 1 mol?
or .600 mol?
how bout this one.. i got two answers again..
2SO2 +2H2O + O2 -----> 2H2SO4
Find the mass of sulfuric acid formed from 3.20 moles of sulfur dioxide.
did you get..
156.8?
or
313.60
or neither?? haha
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wrote...
11 years ago
Based on your question, it seems to read that the acid which is being neutralized is the HCl on the reactant side.  

Since you are given 0.200 mol of Al(OH)3, you would first need to convert it to moles of HCl.  To do this, just use the following conversion: 3 moles HCl/1 mole Al(OH)3.

0.200 mol Al(OH)3 x 3 mol HCl/1 mol Al(OH)3 = 0.600 mol HCl

Thus, it would appear if you use 0.2 mol Al(OH)3, you would neutralize 0.600 mol HCl.  Your products would be AlCl3 (aluminum trichloride) and H20.
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