× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
g
2
2
2
1
Home Q & A Board Biology-Related Homework Help Genetics and Developmental Biology
New Topic  
Mirellia Mirellia
wrote...
Posts: 8
Rep: 0 0
12 years ago
If hemophilia is sex linked recessive trait & the mother has a group of XH  Xh she could have a son?
A)that has normal blood clotting
B)that is a hemophiliac
C) that is a carrier of the hemophilia
D both a & b
E)both a&C
and why and how would the punnet square look
is this right
 --   XH  Xh    
XH                
Xh                  
or

--   XH Xh
XH
Y
Read 542 times
2 Replies

Related Topics

Replies
wrote...
#1
12 years ago
I'm not sure how to work out punnet squares, but I know that such a mother is a carrier. Since she can provide her sons with either a healthy or a mutated X-chromosome, she can have sons with either normal blood clotting, or a haemophiliac son. The answer is D, since both A and b are correct.
wrote...
#2
12 years ago
D is the right answer.  If the mom is a carrier, she can either provide the son with a normal allele or the recessive trait allele.  A male only has one X chromosome, so whatever the mother gives him is what he gets.  The father can only provide a son with a Y, so he has no bearing on x-linked traits here.  Your bottom punnet square has the right set up.  (But the father is obviously providing a Y in order to have a son).
New Topic      
Quick Reply
Bold
Italic
Underline
Strikethrough
Subscript
Superscript
Insert Math Equation
Font Name
Font Color
Align left
Center
Align right
Bullet list
Numbered list
Insert a horizontal rule
Insert a table
Insert a Quote
View source
Explore
Post your homework questions and get free online help from our incredible volunteers
  2079 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Related Images
  
 1063
  
 4557
  
 794
Your Opinion
Previous poll results: What's your favorite math subject?