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rkbrookover rkbrookover
wrote...
Posts: 156
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11 years ago
How to draw alkene formed when 1-heptyne is treated with 1 eq. of HBr.
and
How to draw alkene formed when 1-heptyne is treated with HBr in the presence of peroxide.

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Valued Member
11 years ago
CH3-CH2-CH2-CH2-CH2-C?CH +HBr -----> CH3-CH2-CH2-CH2-CH2-CBr=CH2

CH3-CH2-CH2-CH2-CH2-CBr=CH2  + HBr ------> CH3-CH2-CH2-CH2-CH2-CBr2-CH3

In presence  peroxide,

CH3-CH2-CH2-CH2-CH2-C?CH + HBr -----> CH3-CH2-CH2-CH2-CH2-CH=CHBr

CH3-CH2-CH2-CH2-CH2-CH=CHBr + HBr ----> Two isomeric compounds with equal possibilities of Br atom to be attached to C1 and C2.
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