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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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smooth212 smooth212
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11 years ago
asap

plz help me
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wrote...
#1
11 years ago
There's a formula in your book for this. I don't remember what it is, but I remember using it in chemistry.
wrote...
#2
11 years ago
Ka=[H-]^2/[Acid]-[H-]
*if ratio of Acid concentration and Acid dissociation is greater than 1000, "-[H-]" can be negligible
Ka=[H-]^2/[Acid]
[H-]^2=Ka[Acid]
        =(1*10-6)([0.01])
[H-]=3.16*10^-4

problems like these are usually accompanied with finding the pH

pH=-log[H-]
    =-log[3.16*10^-4]
    =3.5

hope this helps : )
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