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Home Q & A Board Science-Related Homework Help High School Level Science
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RJW RJW
wrote...
11 years ago
In a hypothetical population in Hardy-Weinberg equilibrium, 65 percent of alleles are of the dominant type while the remaining 35 percent are of the recessive type. Calculate the proportion of heterozygous individuals you would expect to see in the F1 generation.
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buhlig Author
wrote...
#1
11 years ago
p^2+2pq+q^2=0
p^2=0.65
q^2=0.35
p=sqrt(0.65)
q=sqrt(0.35)
heterozygous = 2pq
wrote...
#2
11 years ago
let p represent the dominant allele and q the recessive allele frequencies. (pq is heterozygous)
the hardy weinberg equations are as follows: p+q=1 and p^2 + 2pq +q^2 =1 (NOT 0!!!)
given: p= 0.65 and q=0.35, you would plug those values into the 2pq of the second equation to find the number of heterozygotes. you would get 0.455

*the values given are values of p and q, not p squared or q squared because they are the actual allele frequencies of the population.
wrote...
#3
11 years ago
p=.65 q=.35
2pq which is the heterozygotes in the population would equal .455.
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