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Home Q & A Board Science-Related Homework Help High School Level Science
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rjandmj82 rjandmj82
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12 years ago
In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of the allele a is 0.4. What is the percentage of the population that is homozygous for this allele?  (1 point)

A. 4
B. 16
C. 32
D. 36
E. 40
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wrote...
#1
12 years ago
The frequency of the homozygous a genotype is equal to the frequency of the a allele squared. That is the chance of getting an a allele on the first chromosome AND getting an a allele on the second chromosome.

f(aa) = f(a)^2 = 0.4^2 = 0.16

So the answer is B
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