Which of the following genotype frequencies of AA, Aa and aa respectively satisfy the Hardy Weinberg principle?

e.

All of the answers add up to 1, so that condition is satisfied.  The other question is whether or not if p and q are calculated, then p + q = 1:

a.
AA 0.36
Aa 0.55
aa 0.09
so, p = 0.6, so q should equal 0.4, however, 0.4^2 = 0.16, not 0.09, so a is wrong

b.
AA 0.49
Aa 0.42
aa 0.09
so, p = 0.7, so q should equal 0.3, so q^2 = 0.09 and 2pq = 2 x 0.7 x 0.3 = 0.42
so b is correct

c.
AA 0.64
Aa 0.27
aa 0.09
so, p = 0.8, q = 0.2, so q^2 should equal 0.04, not 0.09, so c is wrong

d.
Aa 0.29
Aa 0.42
aa 0.29
p = SQRT(0.29) =0.5385
since p not equal to 0.5, then p cannot equal q and so q^2 cannot equal 0.29, so d is wrong.

So, I would choose answer f, none of the above, since only b is the correct answer.