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juhnjuhn juhnjuhn
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12 years ago
One of the substances in a new alkaline battery decomposes into 0.630 g manganese and 0.370 g oxygen gas.  What is the empirical formula of the substance?
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wrote...
12 years ago
MnO

.630g Mn / 54.9  =  .011 mole

.370g O2 / 32  =  .012 mole
wrote...
12 years ago
Divide through by atomic mass of each element
Mn = 0.630/54.938 = 0.0115
O = 0.370/15.999 = 0.023
Mn:O = 1:2
Empirical formula = MnO2
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