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Home Q & A Board Science-Related Homework Help Mathematics
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lester lester
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11 years ago
? sin²(x)cos(x) dx


? sin(x)/cos^3(x) dx
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wrote...
#1
11 years ago
for the first one use u = sin(x), du = cos(x)
for the second use u = cos(x), du = -sin(x)
wrote...
#2
11 years ago
for #1 u=sinx so then du= -cosx dx and the cos cancels so you get

-?u^2du = - (1/3) u^3 = - (1/3)sin^3(x) + c

for #2 u= cos(x) so du= sin(x)dx

?u^3 du = .25u^4 = .25cos^4(x) + c
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