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UnicornPanda UnicornPanda
wrote...
Posts: 37
Rep: 0 0
11 years ago
I'm having problems working with this limit. I attempted the problem and my work/answer is below. I'm not really good with square roots, let alone limits. Help?! Thanks!

\({\lim_{x\to{\infty}}x_n} \frac{{sqrt{\9{X^{6}}-x}}}{{X^{3}}+8}
=\frac{{sqrt{\9{X^{6}}-x}}}{(x+2)({X^{2}}-2x+4)}
=\frac{{sqrt{\infty-x}}}{(x+2)({X^{2}}-2x+4)}
=\frac{{sqrt{\infty-\infty}}}{(x+2)({X^{2}}-2x+4)}
=\infty\)

That is wrong. 9x^3 is wrong, 0 and Does Not Exist are also wrong. Help!! =/
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Answer accepted by topic starter
BearProBearPro
wrote...
Valued Member
Posts: 382
11 years ago
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