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Home Q & A Board Laboratory Help Upper-Year Courses
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asing96 asing96
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11 years ago
using the following reaction, am bit lost on how to calculate the molarity of NH4OH solution:
AL2(SO4)3+ 6 NH4OH = 2 AL(OH)3+ 3(NH4)2SO4
will greatly appreciate your help on how to calculate the molarity of the Solution to start working on the reaction
please help!
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wrote...
#1
11 years ago
dunno why?
wrote...
#2
11 years ago
Not at all sure what you are doing - But if you have a 25%m/v solution of ammonia this is 25g ammonia in 100mL of solution
This is equivalent to 250g NH3 in 1 litre of solution
 Molar mass NH3 = 17g/mol
250g NH3 = 250/17 = 14.70 mol / litre

Molarity of solution = 14.70 M
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