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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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mickey3099 mickey3099
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11 years ago
What is the sum of the pH and the pOH for a solution at 18°C, where Kw equals 5.8x10^-15?

I have no idea where to start! Any help would be appreciated! Slight Smile
I knew it was something very simple, but sometimes you just tend to overlook the easy things! Thanks soooo much!
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wrote...
#1
11 years ago
-log(5.8 x 10^-15) = 14.24

pH  +  pOH, at 18ºC, must add to 14.24
wrote...
#2
11 years ago
Since at 25°C, Kw = 1.0 x 10^-14, and the sum of pH and pOH in solution would equal 14, I would assume that at 18°C, where Kw = 5.8 x 10^-15, the sum of pH and pOH would be -log (5.8 . 10^-15) or - (-14.24), or 14.24.
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