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butternut butternut
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11 years ago
I know the formula for capacitance is C= (k*A*epsilon0) / d but how do you calculate if there are two different layers of dielectric; with different widths & ks,within the capacitor? Any help would be greatly appreciated.
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wrote...
11 years ago
If the interface is parallel to the plates, then the problem is equivalent to two capacitors in series (charge is the same across the two slabs), each with the width and the k given.

If the interface is normal to the plates, then the problem is equivalent to two capacitors in parallel (voltage is the same across both slabs), each with the width and the k given.
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