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Home Q & A Board Science-Related Homework Help Mathematics
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Julieta Hannu Julieta Hannu
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11 years ago
What are the point of intersection of the two straight lines having the equations

y= 2/3x + 6 and 3x - 2y + 3 = 0
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wrote...
#1
11 years ago
The most simple and efficient way to solve this one is to use substitution; this can be done by plugging one variable (y from the first equation) into the other equation. The equation to solve for x will be:

3x-2(2/3x+6)+3=0

Then solve for x:

3x-4/3x+12=-3
5/3x=-15
x=-9

Now plug x back into whichever equation to solve for y (using the first equation):

y=2/3(-9)+6
y=-6+6
y=0

And your final answer should be: (-9,0)
                                                           x, y

Remember the first number is x, second is y.
wrote...
#2
11 years ago
Easiest way to solve this one is to use substitution. This is done by plugging one variable (y from the first equation) into the other equation. You equation to solve for x will be:

3x-2(2/3x+6)+3=0

Then solve for x:

3x-4/3x+12=-3
5/3x=-15
x=-9

Now plug x back into either equation to solve for y (using the first equation):

y=2/3(-9)+6
y=-6+6
y=0

Final answer (-9,0)
wrote...
#3
11 years ago
using the given you should easily see that 3x - 2 [ 2x / 3 + 6] + 3 = 0
now solve for x { trivial to do } and then find the y value for this x...{ 27/5}
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