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finister finister
wrote...
Posts: 15
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11 years ago
Lister's Disease is an autosomal recessive disease and was studied in the Inuit population of Canada.  It was found that 33 individuals have the disease of the 4300 individuals studied.  What is the allele frequency in this population for each allele?
What is the frequency of carriers of the disease in this population?
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2 Replies
Replies
wrote...
11 years ago
I am rusty on this, so I have to think it through:

let r be the proportion of the recessive gene, then rr is the proportion of the homozygous recessive in the population, rr we are given is 33/4300.

sqrt(33/4267)=0.0876

Now let R be the proportion of the dominate gene in the populations (assumed equal with men and women).

R = 1 - 0.0876 = 0.9124
RR in population is 0.9124^2 =  0.8324


the proportion of Rr  is  2*R*r = 2*0.8324*0.0876 = 0.1458

Apparently the above is correct, my old genetics book is falling apart, so I resorted to Wiki and looked up the Hardy-Weinberg principle, so that is the topic which pertains to this problem.  You may need more detail than given here to explain it.

Please check for errors, as I say, I am rusty on this.
Answer accepted by topic starter
tonesacktonesack
wrote...
11 years ago
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