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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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irina irina
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Posts: 919
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11 years ago
I have 96 L (the limiting factor) of a reagent.  This represents 85 % of the total volume.  How do I determine the volume needed to make up the remaining 15 % neede to make this blend?
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wrote...
#1
11 years ago
put the numbers into a porportion and  cross multiply
wrote...
#2
11 years ago
96 liters----------->85%
X=??---------------->15%
85X=96*15
X=(96*15)/85=288/17=16.94
wrote...
#3
11 years ago
96(100/85)(15/100)=
96(15/85)=16.94117647...=
16.94(2D)
wrote...
#4
11 years ago
Okay.  The only way I can think of is to set up a proportion and solve for the unknown factor.  So it would be:    
95 L .....  X
------  =  -------
0.85 .... 0.15

95 * 0.15 = 0.85X         (Solve for X)
14.25 = 0.85X              (Divide both sides by 0.85)
16.764 = X                  (So the additional 15% of the volume is approximately 16 3/4 L)

But that's if it is 95 L and not 96 L (your title says 95 L and your description says 96 L)

Hope that helps!
irina Author
wrote...
#5
11 years ago
Thx!
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