Top Posters
Since Sunday
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
r
4
New Topic  
datewing datewing
wrote...
Posts: 48
Rep: 0 0
11 years ago
Having a little trouble with the use of trigonometric identities in proving some of these statements. These are what i need to prove


sin^2 x (csc^2 x + sec^2x) = sec^2x

cos 0 (sin 0 +(cos^2 0)/sin 0) = cot 0

the zeros on the last problem take the place of the little 0 with the line through the middle that you see in math and that i didnt know how to replicate on the computer. Thanks to anyone who can help.
Read 517 times
5 Replies
Replies
wrote...
11 years ago
With these, always start by converting everything into sin and cos - that way you can see what you're working with  (and you only have to learn the identities for sin and cos, and not for tan, csc, sec or cot)...


LHS = Sin^2x * (1/Sin^2x + 1/cos^2x)
= Sin^2x (cos^2x + Sin^2x)/[Sin^2xCos^2x]

remember that Sin^2x + cos^2x = 1
= sin^2x/[SIn^2xCos^2x]
Cancel out the SIn^2x
= 1/cos^2x = sec^2 x = RHS

RHS = cot0 = 1/tan0 = 1/(sin0/cos0) = cos0/sin0
LHS = cos 0 (sin 0 +(cos^2 0)/sin 0)
= cos0/sin0) * (sin^20 + cos^20)
= cos0/sin0 * 1
= RHS
This doesn't equal the right hand side unless you meant....
wrote...
11 years ago
sin^2 x (csc^2 x + sec^2x) = sec^2x
LHS = sin^2 x (csc^2 x + sec^2x)
       = sin^2 x csc^2x + sin^2x sec^2x
       = 1 + (1-cos^2x)sec^2x                       (sinx cscx =1;   sin^2x = 1-cos^2x)
       = 1 + sec^2x - 1                                 (secx cosx=1)
       = sec^2x  RHS , proved

cos 0 (sin 0 +(cos^2 0)/sin 0) = cot 0    

LHS = cos 0 (sin 0 +(cos^2 0)/sin 0)
        = cos 0 ( sin^2 0 + cos^2 0 )/sin 0
        = cos 0/sin 0    [sin^2 0 + cos^2 0=1]
        = cot 0 =RHS
wrote...
11 years ago
sin^2(x) * (csc^2(x) + sec^2(x)) = sec^2(x)
sin^2(x) * (1/sin^2(x) + 1/cos^2(x)) = sec^2(x)
1 + sin^2(x)/cos^2(x) = sec^2(x)
(sin^2(x) + cos^2(x)) / cos^2(x) = sec^2(x)
1 / cos^2(x) = sec^2(x)
sec^2(x) = sec^2(x)

cos(x) * (sin(x) + cos^2(x))/sin(x) = cot(x)
cos(x) * ((sin^2(x) + cos^2(x))/sin(x) = cot(x)
cos(x) / sin(x) = cot(x)
cot(x) = cot(x)
Answer accepted by topic starter
RiveraCIRiveraCI
wrote...
Posts: 101
Rep: 0 0
11 years ago
Sign in or Sign up in seconds to unlock everything for free
1

Related Topics

wrote...
11 years ago
LHS                                                                  RHS
sin^2x(1/sin^2x + 1/cos^2x)                               sec^2x
sin^2x(cos^2x + sin^2x)/cos^2x sin^2x
where cos^2x + sin^2x=1
then
sin^2x(1/cos^2x sin^2x)
sin^2x/(cos^2x sin^2x)
1/cos^2x
sec^2x =                                                       sec^2x


cos 0 (sin 0 +(cos^2 0)/sin 0)
cos 0 (sin^2 0 + cos^2 0)/sin 0
where sin^2 0 + cos^2 0 =1
then
cos 0 (1)sin 0
cos 0/sin 0
cot 0                                  =              cot 0

hope i have answered your question.good luck.
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  1299 People Browsing
 123 Signed Up Today
Related Images
  
 128
  
 296
  
 247
Your Opinion
Who will win the 2024 president election?
Votes: 3
Closes: November 4