What is the mass of 0.5 acre-foot of water? Calculate the annual cost of pumping water to the average househol?

are you taking chem 1C too?
I can help ya with this problem I just finished it today.

Ok so how I did it was by taking converting the .5 acre-foot of water to liters which comes out to be...616740.91877 Liters. And water can be directly converted from liters to kilograms so.... 616740.91877 Liters is equal to 616740.91877 Kg. So that solves the first part.

The next part is what we just learned in class in regards to potential energy. That equation is

Potential energy = Mass x Gravity x Distance
 
The mass is easy thats just the 616740.91877kg from before. The gravity is a constant that he gave which is equal to 9.81 meters/sec. The distance you need to convert from feet to meters. So 2000 feet translates to 609.6 Meters.  I think it's like 1 meter=3.38 feet.

We then have.............

Mass=616740.91877
Grav= 9.81
Distance= 609.6

Multiply those all together to get your Potential energy.
I'll finish writing the rest of this problem if you need help still after I get back from math11b.


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