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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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Micheal Micheal
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11 years ago
reaction with Ca(OH)2.

2CO2 (g) + Ca(OH)2 (ag) ==> Ca(HCO3)2.
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#1
11 years ago
Moles Ca(HCO3)2 = 100 g/ 162.118 g/mol = 0.617
The ratio between CO2 and Ca(HCO3)2 is 2 : 1
Moles CO2 = 2 x 0.617 =1.234

T = 25 + 273 = 298 K
p = 765 / 760 = 1.0 atm

V = nRT / p = 1.234 x 0.0821 x 298 / 1.0 =30.2 L
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#2
11 years ago
Find the weight of Ca(HCO3)2:
Ca = 40 grams
H = 1 x 2 = 2 grams
C = 12 x 2 = 24 grams
O = 16 x 6 = 96
Added together they total 162 grams per mole.  Given 100 grams is less than a mole, divide it by 162 to see what part of a mole you have.  100 / 162 = .62 moles.  Now find the weight of CO2:
C = 12
O = 16 x 2 = 32
Added together they total 44 grams per mole of CO2.  In the formula the ratio of CO2 to Ca(HCO3)2 is 2:1.  Since 1 = .62 moles, then 2 = .62 x 2 = 1.24 moles.  1.24 moles x 44 grams / mole = 54.56 grams of CO2 needed.
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