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smokeypal23 smokeypal23
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11 years ago
How do you calculate the molarity of a solution of Ba(OH)2 if the pH of the solution is 10.5.
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11 years ago
pOH = 14 - 10.5 =3.5
[OH-]= 10^-3.5 =0.000316 M
Molarity Ba(OH)2 = 0.000316/2 =0.000158 M
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iliketospamiliketospam
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11 years ago
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