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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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michal.levy michal.levy
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11 years ago
30.1g of Sulfur trioxide is dissolved into 600ml of water to form sulfuric acid. What the molarity and normality?

The moles of Surfur trioxide is .367 moles
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#1
11 years ago
Molarity = Nº mol solute/ Volumen solution (L)

M = 0.367 mol/ 0.6 L = 0.61 mol/L

Normality = equiv # x Molarity

Normality = W * M

W in this case (sulfuric acid) it would be the amount of H in the formula (2).

N= 0.61 * 2 = 1.22 eq/L = 1.22 N
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