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bobaholic bobaholic
wrote...
Posts: 29
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11 years ago
Would you use integral by parts for integral of tanx? or is there an easier way?
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wrote...
11 years ago
tanx=sinx/cosx;
\({\int_{-N}^N sinx/cosx \,dx}\) ;
let u=cosx;
du=-sinx dx

\({\int_{-M}^M -1/u \,du}\) ;

its integral of -1/u= -ln (u)=-ln cosx

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