× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
r
4
L
4
3
d
3
M
3
l
3
V
3
s
3
d
3
a
3
g
3
j
3
Home Q & A Board Science-Related Homework Help Mathematics
New Topic  
blahhumbug blahhumbug
wrote...
Posts: 8
Rep: 0 0
7 years ago
Twelve dieters lost an average of 9.8 pounds in 6 weeks when given a special diet plus a "fat-blocking" herbal formula. A control group of twelve other dieters were given the same diet, but without the herbal formula, and lost an average of 8.8 pounds during the same time. The standard deviation of the "fat-blocker" sample was 2.6 and the standard deviation of the control group was 2.8. Find the 95% confidence interval for the differences of the means.
Read 1269 times
1 Reply

Related Topics

Replies
Answer rejected by topic starter
wrote...
#1
Educator
7 years ago
Mean 1: 9.8
Mean 2: 8.8
N1: 12
N2: 12
Std Dev.1: 2.6
Std Dev.2: 2.8

z for 95% CI= 1.96

Difference between means:
M1-M2=9.8-8.8=1
sd=5.1596; se=1.103

Margin of error = \pm 1.96(0.1103)
95% CI of difference:
-1.0319 <1< 3.0319

Right option is

B)

-1.0<mu1-mu2<3.0
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1554 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 470
  
 356
  
 188
Your Opinion
Do you believe in global warming?
Votes: 488
Previous poll results: Does a gender wage gap exist in America?