Can anyone help me with this i did the experiment but i am not really understanding the questions.
Pepsin Experiment Follow the instructions in the Lab Instruction Worksheet for Activity 3, fill in the table, and answer the accompanying questions.
Treatment Reagent 1 Reagent 2 Reagent 3 Boiled Optical Density
1 pH 2.0 buffer BAPNA Pepsin + 0.0
2 pH 2.0 buffer BAPNA Pepsin - 0.40
3 pH 2.0 buffer Water Pepsin - 0.0
4 pH 2.0 buffer BAPNA Water - 0.0
5 pH 7.0 buffer BAPNA Pepsin - 0.03
6 pH 9.0 buffer BAPNA Pepsin - 0.0
Write the number of the treatment that is intended to show that the BAPNA used in the experiment was intact, rather than degraded into small fragments. ____________________
Based on the treatments in this experiment, what is the pH optimum of pepsin? _____________
When stomach contents enter the duodenum, the pH is neutralized by secretion of bicarbonate (HCO3-). What happens to the activity of pepsin under these conditions?
Lipase Experiment Follow the instructions in the Lab Instruction Worksheet for Activity 4, fill in the table, and answer the accompanying questions.
Treatment Reagent 1 Reagent 2 Reagent 3 Reagent 4 pH
1 pH 7.0 buffer Bile Salts Veg. Oil Lipase 6.21
2 pH 7.0 buffer Water Veg. Oil Lipase 6.72
3 pH 9.0 buffer Bile Salts Water Lipase 9.00
4 pH 7.0 buffer Bile Salts Veg. Oil Water 7.00
5 pH 2.0 buffer Bile Salts Veg. Oil Lipase 2.0
6 pH 9.0 buffer Bile Salts Veg. Oil Lipase 8.97
Based on the results above, which statement about lipase is correct? 1) Lipase is fully active at pH 9.0, 2) Lipase is partially active at pH 9.0, 3) Lipase is completely inactive at pH 9.0 _______________________
As you perform the experiment, note that vegetable oil does not mix with the aqueous solution initially, but it does so after mixing and incubating for all but one treatment. What component of the reaction allows the oil to mix with the aqueous solution? _________________________
Compare treatments 1 and 2. Why is the pH of treatment 1 lower than the pH of treatment 2?
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