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smrrdn smrrdn
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11 years ago
I just don't understand how to do this.  Someone told me to write the energy as E = 140 * 3*10^8 (for the speed of light), but why would the speed of light count as the energy too?  I thought the energy would just be 140 keV?  I am just confused.  Please help Frowning Face
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11 years ago
As a massless particle photon energy is E = hf = hc/L= 140 KeV = 2.24307E-14 Joules.  

(Recommend you not return to that "someone" for physics advice again.  That someone has mixed eV with meters/sec, so the units are inconsistent.  You must convert to Joules to get L in meters and frequency in cycles per second (aka Hertz).)  [See the source below for an excellent unit conversion web site.]

So L = hc/E = ? meters; where h is Planck's constant in the kms SI units, c ~ 299E6 mps, and E is in Joules above.  You can do the math.

And f = E/h = ? cycles per sec (Hertz).  You can do the math.

The speed of the photon is, of course, c, the speed of light.
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