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smita smita
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11 years ago
Calculate the concentration of sodium benzoate that must be present in 0.20M solution of benzoic acid, to produce a pH of 4.00. Ka= 6.3e-5.

Ans= 0.13M, pls show how to get that.
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wrote...
11 years ago
pKa = - log Ka = 4.20

4.00 = 4.20 + log [benzoate]/ [benzoic acid]

10^-0.20= 0.63

0.63 = [benzoate]/ 0.20

[benzoate]= 0.13 M
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