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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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RiseofEvil RiseofEvil
wrote...
11 years ago
Urine (pH = 6.0)
Blood (pH = 7.4)
Bile (pH = 8.0)

How do I determine the concentration?
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wrote...
#1
11 years ago
pH = -log[H3O+]

Urine  [H3O+] = 10^-6.0 = 1.00 x 10^-6 M H3O+
Blood  [H3O+] = 10^-7.4 = 3.98 x 10^-8 M H3O+
Bile [H3O+] = 10^-8.0 = 1.00 x 10^-8 M H3O+

pKa = pH*pOH = 14 and Ka = [H3O+][OH-] = 1.00 x 10^-14

pOH = Ka/[H3O+]
Urine  pOH = 1.00 x 10^-14/1.00 x 10^-6 = 1.00 x 10^-8
Blood pOH = 1.00 x 10^-14/3.98 x 10^-8 = 2.51 x 10^-7
Bile  pOH = 1.00 x 10^-14/1.00 x 10^-8 = 1.00 x 10^-6
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