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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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NURGirl NURGirl
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11 years ago
A solution prepared by dissolving 3.00g of ascorbic acid (vitamin C,C6H8O6 ) in 50.0g of acetic acid has a freezing point that is depressed by delta T = 1.33 degreeC below that of pure acetic acid.
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nurhannurhan
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11 years ago
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11 years ago
moles ascorbic acid = 3.00 g/176.12 g/mol= 0.0170
m = 0.0170 / 0.0500 Kg= 0.34
1.33 = 0.34 x Kf
Kf = 3.91 °C/m
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