Determine the identity of the daughter nuclide from the alpha decay of 222 86 R

Hi sonikudi,

After an alpha decay, your atom would have 4 less mass unit and 2 less proton. And since the proton number changes, you would have to change the element according to new proton number.

22286 Rn -----> 21884PO + alpha particle

To determine the binding energy, you need to find the mass defect first.
F-19 nucleus would have 9 protons and 10 neutrons. So the mass should be
9*1.00728 + 10*1.008665 = 19.15217 amu

Therefore the mass defect would be 19.15217 - 18.99840325 = .15376675 amu
For every amu you would have 931 MeV of energy. Therefore the binding energy is .15376675*931 = 143.157 MeV

Hope this helps,
Laser

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