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nyno2010 nyno2010
wrote...
Posts: 31
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11 years ago
Use a standard normal table to find the Z-Score that corresponds to the percentile P50

Find the Z-score that has 95.91% of the distribution's area to the left.

Find the Z-score that has 78.52% of the distribution's area to the right.

Find the Z-score for which 90% of the distribution's area lies between -z and z


Please help me out. Thanks.
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2 Replies
Replies
wrote...
11 years ago
Do an image search for z-score tables:
P50 = 0
z-score for P(.9591) = 1.74

You want to do 1 - .7852- .2148, because z-score tables always tell us the probability to the left.
So find the zscore of .2148 = -.79

You want the z-score that contains 45% (.95) above P50 and 45% below P50 (.05) which gives the 90% area:  z=1.64 and z=-1.64
Answer accepted by topic starter
tuataratuatara
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11 years ago
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