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Home Q & A Board Science-Related Homework Help Mathematics
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Imageek Imageek
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10 years ago
Math has never really been my main subject .But I was wondering how I would solve an equation like this:
2(4a-12)+3a=6a+1
Im not really sure where to start on it first . I tryed asking my teacher and I still don't understand what she is talking about .
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sms440sms440
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#1
10 years ago
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#2
10 years ago
2(4a-12)+3a=6a+1

First multiply everything out
8a-24+3a=6a+1

Now add together like terms on each side

11a-24=6a+1

Now subtract 6a from both sides so that it is only on one side
5a-24=1

Subtract -24 from both sides

5a=25

Divide both sides by 5

a=5
wrote...
#3
10 years ago
2(4a-12)+3a=6a+1

8a - 24 + 3a = 6a + 1 {distribute the 2 on the left}

11a - 24 = 6a + 1 {combine 8a & 3a on the left}

5a - 24 = 1 {subtract 6a from both sides}

5a = 25 {add 24 to both sides}

a = 5 {divide both sides by 5}
wrote...
#4
10 years ago
8a-24+3a=6a+1
8a-24=3a+1
8a=3a+25
5a= 25
a= 25/5= 5
wrote...
#5
10 years ago
2(4a-12)+3a=6a+1
=2*4a-2*12+3a=6a+1
=8a-24+3a=6a+1
sorry i didn't get the =6a+1 so i considered you add them together with like terms so i got

11a-24=6a+1

hope this helped if it didn't then good luck.
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