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smith0021 smith0021
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10 years ago
N2(g)+3H2(g) ---->2NH3(g)  DeltaH of the reaction= -91.8kJ

N2(g)+4H2(g)+Cl2(g)--->2NH4Cl(s) DeltaH of reation=-628.8kJ

NH3(g)+HCl(g)---->NH4Cl(s)   DeltaH of reation=-176.2kJ
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wrote...
10 years ago
This is very simple:

Multiply the third equation by -2.  The (-) will reverse the direction of the reaction.
Multiply the first reaction by -1.
Sum the modified first and third and add the second.  You will be left with
H2(g) + Cl2(g) ---> 2HCl(g).

Now perform the same operations on the DeltaH. e.g., third value times -2, first value times -1.  Add them now and add the second value.  That's it.

(-2)*(-176.2) + (-1)*(-91.8) + 1*(-628.8)
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