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MrSir MrSir
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10 years ago
A light board, 10 m long, is supported by two sawhorses, one at one edge of the board and a second at the midpoint. A 40-N weight is placed between the two sawhorses, 3.0 m from the edge and 2.0 m from the center. What forces are exerted by the sawhorses on the board?

Any help would be appreciated.
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10 years ago
Similar Question
A light board, 10 m long, is supported by two sawhorses, one at one edge of the board and a second at the midpoint. A 40-N weight is placed between the two sawhorses, 3.0 m from the edge and 2.0 m from the center. A second weight, with a weight of 15 N, is placed on the far end from the board. What forces are exerted by the sawhorses on the board?

Answer
Let's suppose the point of rotation is the midpoint of the board.
then: 3W-5R = 0 ( R is the normal of the sawhorse at theedge, W is the weight)
R = 3W/5 = 24N
The system is in equilibrium so R+N-W = 0 ( N is the forceexerted by the sawhorse at the midpoint)
N = W-R
N =16N
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