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tigeria2013 tigeria2013
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10 years ago
Consider that there is 26.38 g NaCl in a solution that has a total volume of 1,780 mL with a density of 0.8495 g/mL. A) What is the molarity of NaCl? B)What is the mass/mass %? C)What is the molality?

Any help would be appreciated. I'm drawing a blank on this. D:
Source  SCIN131
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wrote...
10 years ago
26.38 g NaCl: n = m/M = 26.38 / 58.5 = 0.451 mol NaCl.

A) Molarity = n / v = 0.451 / 1.78 = 0.253 mol/L.

B) d = m / v Rightwards Arrow m = 1780 x 0.8495 = 1512.11 g.
Rightwards Arrow 26.38 / 1512.11 = 0.0174 = 1.74%.

C) 1512.11 g - 26.38 g = 1485.73 g water = 1.48573 kg water.
Rightwards Arrow Molality = 0.451 / 1.48573 = 0.30355 mol/kg.
wrote...
10 years ago
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