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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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HIGVICIOUS HIGVICIOUS
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10 years ago
Ammonia gas decomposes according to the equation: 2NH3(g) → N2(g) + 3H2(g) If 20.0 L of nitrogen is formed at STP, how many liters of hydrogen will be produced (also measured at STP)?
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#1
10 years ago
Thank you so much
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10 years ago
This question reminds me of

Sample Question
Ammonia gas decomposes according to the following equation:

2 NH 3(g) ---> N 2(g) + 3H 2(g)

If 15.0 L of nitrogen is formed at STP, how many liters of hydrogen will be produced (also measured at STP)?
Additional Details
90.0 L
15.0 L
30.0 L
45.0 L

Solution
answer: 44.8 L H2
ok so a basic conversion you should kno is 22.4 L = 1 mol gas at STP

so 15 L nitrogen x (1 mol /22.4 L) = 0.67 mol N2
then by basic conversion
0.67 mol N2 x (3 mol H2/1 mol N2) = 2 mol H2
then we convert the moles of hydrogen gas back to liters
2 mol H2 x (22.4 L / 1 mol H2) = 44.8 L H2
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