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How to integrate using inverse trigonometric substitution (Question 6)

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(04:28:51) (895566): -1' OR 2+803-803-1​=0+0+0+1 --
(04:28:51) (895566): -1' OR 3+803-803-1​=0+0+0+1 --
(04:28:51) (895566): -1' OR 3*2<(0+5+80​3-803) --
(04:28:51) (895566): -1' OR 3*2>(0+5+80​3-803) --
(04:28:52) (895566): -1' OR 3*2<(0+5+10​4-104) or 'Sqobl2zu'='
(04:28:52) (895566): -1" OR 2+23-23-1=0​+0+0+1 --
(04:28:52) (895566): -1" OR 3+23-23-1=0​+0+0+1 --
(04:28:53) (895566): -1" OR 3*2<(0+5+23​-23) --
(04:28:53) (895566): -1" OR 3*2>(0+5+23​-23) --
(04:30:48) (895566): @@uH6bb
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