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Brad_was Brad_was
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5 years ago
When 1-iodo-1-methylcyclohexane is treated with NaOCH2CH3, the more highly substituted alkene product predominates. When KOC(CH3)3 is used instead, the less highly substituted alkene product predominates. Offer an explanation.
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Organic Chemistry

Organic Chemistry


Edition: 9th
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samanthajones10samanthajones10
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5 years ago
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