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Home Q & A Board Science-Related Homework Help High School Level Science
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rjay92 rjay92
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Posts: 66
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11 years ago
A population of mice is at Hardy-Weinberg equilibrium at a gene locus that controls fur color. The locus has two alleles: M and m. A genetic analysis of one population reveals that 60% of its gametes carry the M allele. What percentage of mice contains both the M and m allele?

The answer is 48%. Can anyone explain why?
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RJW
wrote...
#1
11 years ago
P^2 + 2pq + q^2 = 1
wrote...
#2
11 years ago
Using the equation above where M = .6 and m = .4  and you multiply together.  Read your book for the distribution.
wrote...
#3
11 years ago
According to Hardy-Weinber equation #2, the frequency of heterozygotes in a population is given by 2 * frequency of dominant allele * frequency of recessive allele or, in this case, 2(0.6)(0.4) = 0.48.  The reason it's multiplied by 2 is that some combinations of alleles are Mm and some are mM, so we have to add these two possible combinations..

A Punnett square of probabilities would look like:

_____0.6_______0.4__
0.6__0.36_____0.24__
0.4__0.24_____0.16__
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