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Home Q & A Board Science-Related Homework Help High School Level Science
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buidatsnpha buidatsnpha
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11 years ago
At a locus with a dominant and a recessive allele in a hardy weinberg equilibrium, 16% if the individuals are homozygous for the recessive allele. What is the frequency of the dominant allele in the population?

The answer is 0.6

but I have no clue how to set it up. thanks for any help
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wrote...
#1
11 years ago
In Hardy-Weinberg equilibrium:
p =dominant allele frequency
q = recessive allele frequency
p + q = 1
p^2 + 2pq + q^2 = 1

In your example, q^2 = .16 so q = .4
p + .4 = 1
so p = .6
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