Simply use trigonometry and the formula for acceleration. Of course gravity will be split into x and y components because of the given angle. So use tan27degrees and solve for the y component of gravity acting on the truck, and then use cos27 to solve the X component of the trucks acceleration Then calculate the acceleration of the truck will be calculated. Acceleration is equal to final velocity minus initial velocity divided by time. Here we go
![Slight Smile](https://biology-forums.com/Smileys/default/1f642.png)
Acceleration of truck is equal to -17.24 meters per second squared note this is the hypotenuse component of the truck's acceleration. X and Y still need to be solved.
Acceleration of gravity in the y component is still the same, 9.81 m/s squared.
Acceleration of gravity in the y component is 9.81m/s squared (down)
Acceleration of the truck in the y component is approximately 7.827m/s squared (down)
Acceleration of gravity in the X component is -19.25m/s squared.
Acceleration of truck in the X component is -15.36m/s squared.
Now we simply add our like terms,(x and y components).
So total force in the X component is -34.61m/s squared
And total force in the Y component is 17.637 m/s squared (down)
Tips: Always assign a direction ( up and down as positive or negative)
Make triangles for each force of acceleration. It will make these types problems a breeze =)
Hopefully this answer is right, be sure to let me know, good luck.