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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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lgraha13 lgraha13
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11 years ago
A.)If the molar solubility of CaF2 at 35degC is 1.24x10^-2mol/L, what is Ksp at this temperature??
B.) It is found that 1.1x10^-2g of SrF2 dissolves per 100mL of aqueous solution at 25degC. Calculate solubility product constant.

Answers:
A.)Ksp = 7.63x10^-9
B.) Ksp= 2.7x10^-9

But how?! Help!
Thanks!
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julius_6483julius_6483
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#1
11 years ago
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4 years ago
thank you
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