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riyachand riyachand
wrote...
Posts: 20
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11 years ago
What is the normality of a barium hydroxide solution if 33.6 mL require 71.2 mL of 4.72 M hydrochloric acid solution?
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3 Replies
Replies
wrote...
11 years ago
N1V1=N2V2

     let us take as N1= Normality of barium hydroxide
                            V1= Volume of barium hydroxide
                           N2= Normality of HCl
                           V2= Volume of HCl
HCl is a mono basic acid therefore its molarity= normality
Now substitute the values in the formula
            N1V1=N2V2  
           N1X33.6=4.72X71.2
           N1= 4.72 X 71.2/33.6
THATS IT.
wrote...
11 years ago
i think that if you calculate the moles of barium hydroxid that you have, then calculate the molarity of the Ba(OH)2 solution, and multiply by two, you get the normality.  The multiplication step is because there are two hydroxides for each molecule of Ba(OH)2.
hope this helps!
Answer accepted by topic starter
tosdamosttosdamost
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Posts: 23
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11 years ago
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