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livestrong136 livestrong136
wrote...
Posts: 324
Rep: 7 0
11 years ago
1. Consider the following reaction:
      2 HI (g) → H2 (g) + I2 (g)
Assume that an experiment is carried out in which the starting concentration of HI (g) is 0.100 mol/L. No products are present at the beginning of the reaction. When equilibrium is established, the concentration of H2 (g) is 1.73 x 10-2 mol/L. Calculate the equilibrium constant for the above reaction.


2. The compound NOCl decomposes to nitric oxide and chlorine according to the following equation:
   2 NOCl (g) → 2 NO (g) + Cl2 (g)
Suppose that 0.810 mol NOCl is placed in a 4.00-L flask at a given temperature. When equilibrium has been established, it is found that the concentration of Cl2 is 0.0105 M. Calculate the equilibrium constant for this reaction.


3. Nitrogen and oxygen react to produce nitric oxide according to the following equation:
      N2 (g) + O2 (g) → 2 NO (g)
The equilibrium constant for this reaction is 1.70 x 10-3. Suppose that 0.680 mol N2 and 0.600 mol O2 are mixed in a 2.00-L reaction vessel. What will be the concentrations of N2, O2, and NO when equilibrium is established? (Hint: assume that the amounts of N2 and O2 that react are small—less than 10% of the starting amounts—and check your assumption when you have solved the equation.)
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7 Replies
Replies
wrote...
Valued Member
11 years ago
I think the correct way to answer them is by using the Keq= [H2][I2]/ 2*[HI]
By using the molar ratios from the balanced equation,  if 0.1 mol/L= [HI] reacted to give us at equilibrium 1.73*10^-2 mol/L=[H2], then the [I2] also at equilibrium should be 1.73*10^-2 because they both equal in terms of the molar ratio, this leaves keq= (1.73*10^-2)/ 2*(0.1) =)
The same method goes by for question 2, but we need to find the concentration by dividing by 4L because it was not directly given like in question 1.
B.Sc in Biology
M.Sc Neuroscience
PhD. Candidate in Neuroscience


livestrong136 Author
wrote...
11 years ago Edited: 11 years ago, livestrong136
Ok. so the answer for #1 would be

keq= (1.73*10^-2)/ 2*(0.1) = 0.01614

But u said the equation is [H2][I2]...so wouldn't it be keq= (1.73*10^-2)(1.73*10^-2)/ 2*(0.1) =
Post Merge: 11 years ago

Btw, thumps up  Slight Smile
wrote...
Valued Member
11 years ago
I'm sorry I forgot to type in the squared... and that's right! =) Good luck!
B.Sc in Biology
M.Sc Neuroscience
PhD. Candidate in Neuroscience


livestrong136 Author
wrote...
11 years ago
and sorry I am still confused about #2, can u put it in steps, what r we dividing 4L by?Neutral Face
wrote...
Valued Member
11 years ago
We dont have the concentration of NOCL, but we have the number of moles and volume, so its concentration is 0.8/4... that's it =)
B.Sc in Biology
M.Sc Neuroscience
PhD. Candidate in Neuroscience


livestrong136 Author
wrote...
11 years ago
oooh ok, thnx, just to make sure, it would be like this

0.810/4 = 0.2025

= (0.0105)2 / 20.2025

and btw, do u know #3???
Answer accepted by topic starter
ehd123ehd123
wrote...
Valued Member
Top Poster
Posts: 778
11 years ago
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B.Sc in Biology
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