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asaf asaf
wrote...
Posts: 32
Rep: 2 0
13 years ago
A calcite exist in 2 Crystal forms:
1) Calcite
2) Aragonite
The transfer reaction between them is given: CaCO3 (ara) -> CaCO3 (cal).

In addition, given is the deltaG (change in free energy of the reaction) at 298K, 1bar:
dGm (in standard situation) = -795 [J/mol].

The change in molar volume for the reaction is: deltaV(m) = 2.75 [ml/mol]

Please calculate, in which pressure there will be equilibrium between the 2 forms of the calcite? [bar]
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Replies
wrote...
Donated
Trusted Member
13 years ago
Wat did you end up getting for this?
asaf Author
wrote...
13 years ago
DONT ASK Thinking Face
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