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Home Q & A Board Science-Related Homework Help Physics
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nurhan nurhan
wrote...
Posts: 13
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11 years ago
r1=4+- 0.2 and r2=4+-0.3....[read as 4 plus or minus o.2 and 4 plus or minus 0.5 respectively]

so....what is the equiv. resistance in series and parallel?
heyy..I know the formulas...I just cant arrive at the correct answer.
temme how you worked it out.
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wrote...
#1
11 years ago
In series it would be:

8 +- 0.5

In parallel it would be:

2 +- 0.13

If you want a detailed explanation send me an e-mail.
wrote...
#2
11 years ago
The  + and - are resistance tolerances.
The general formula is:
When in series:   Rt = R1 +R2 +R3+.......
When in Parallel: Rt = 1/R1 + 1/R2 + 1/R3+....
You solve the total resistance. If you want to consider the tolerance:
R1 = 4.2 and 3.8  and ......  you know the next.
wrote...
#3
11 years ago
Series, resistors add, and the tolerance adds also

R = 4 + 4 = 8
Rhi = 4.2 + 4.3 = 8.5
Rlo = 3.8 + 3.7 = 7.5
R = 8 ± 0.5

parallel

R = 4/2 = 2
Rhi = 4.2*4.3/(4.2+4.3) = 2.12
Rlo = 3.8*3.7/(3.8+3.7) = 1.87
R = 2 ± 0.12
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