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xlr300 xlr300
wrote...
Posts: 2009
9 years ago
What mass of CaCl2 is required to prepare 3.20 L of 0.850 M CaCl2 solution?
A) 302 g
B) 139 g
C) 101 g
D) 78.9 g

Textbook 
Introduction to Chemical Principles

Introduction to Chemical Principles


Edition: 11th
Author:
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Answer accepted by topic starter
dustyparticledustyparticle
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Posts: 1979
9 years ago
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